Block hanging from spring when a second block is added

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SUMMARY

The discussion centers on calculating the oscillation frequency of a block-spring system when a second identical block is added, causing the original block to sag by 3.00 cm. The user attempted to apply Hooke's Law (F = -ky) with a force of 2mg and a displacement of 0.03 m to find the spring constant (k). However, the subsequent calculation of the period using T = 2π√(m/k) yielded incorrect results. The sag of 3 cm indicates the spring's extension due to the combined weight of the two blocks.

PREREQUISITES
  • Understanding of Hooke's Law (F = -ky)
  • Basic knowledge of oscillatory motion and frequency calculations
  • Familiarity with the concepts of mass (m) and gravitational force (g)
  • Ability to manipulate algebraic equations for solving spring constants and periods
NEXT STEPS
  • Calculate the spring constant (k) using the sag of 3 cm and the total weight of the two blocks.
  • Learn about the relationship between mass, spring constant, and oscillation frequency.
  • Explore the derivation of the formula for the period of oscillation in spring systems.
  • Investigate the effects of multiple masses on spring systems and their oscillation characteristics.
USEFUL FOR

Physics students, mechanical engineers, and anyone studying dynamics and oscillatory systems will benefit from this discussion.

dtesselstrom
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A block hangs in equilibrium from a vertical spring. When a second identical block is added, the original block sags by 3.00 cm. It wants to know the oscillation frequency of this problem.
So far I tried solving for F=-ky with F being 2m*g and y equal to .03. I solved for k and plugged that into T=2pi sq root of m/k this however said it was wrong. Any information on how to approach this would be nice.
 
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dtesselstrom said:
A block hangs in equilibrium from a vertical spring. When a second identical block is added, the original block sags by 3.00 cm. It wants to know the oscillation frequency of this problem.
So far I tried solving for F=-ky with F being 2m*g and y equal to .03. I solved for k and plugged that into T=2pi sq root of m/k this however said it was wrong. Any information on how to approach this would be nice.
The 3cm sag comes from adding 1m. How much do you think the spring is streteched from its natural length with the 2m hanging on it?
 

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