A block with mass m1 = 9.4 kg is on an incline with an angle θ = 31.0° with respect to the horizontal. There is also a massless rope that pulls horizontally to prevent the block from moving. What is the tension in the rope?
Fg = m*g
Fg,x = m*g*sin 31 = Tx (?)
Fg,y = m*g*cos 31 = Fn
Ff = u*Fg,y
The Attempt at a Solution
Fg = 9.4kg*9.8m/s^2 = 92.12N
Fg,x = Tx(?) = 92.12N * cos 31 = 84.156N
Fg,y = Fn = 92.12N * sin 31 = 37.469N
Ff = u * Fn
I had a value for the coefficient of static friction, but that was for a system with a spring (.292), so I don't think that'll work here. I also have one for kinetic friction (.212), but that might not apply here. I'm a little unsure in finding the tension in the x-direction, since I'm pretty sure if I can find that, I can find the overall tension using Tx/cos31. But after that, I'm stuck.