Calculate Acceleration, Friction & Speed on 30° Incline | Block Homework

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SUMMARY

The discussion focuses on calculating the acceleration, friction, and speed of a 3.00-kg block sliding down a 30.0° incline over a distance of 2.00 m in 1.50 s. The calculated acceleration is 1.78 m/s², and the coefficient of kinetic friction (Uk) is determined to be 0.787. Participants identified a sign error in the equations governing the forces acting on the block, specifically in the friction force and gravitational components. Correcting the signs in the equations is crucial for accurate results.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Familiarity with free body diagrams (FBD)
  • Knowledge of kinetic friction and its coefficient
  • Basic trigonometry for resolving forces on an incline
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  • Review the derivation of forces on inclined planes
  • Practice drawing and interpreting free body diagrams (FBD)
  • Learn about the effects of friction on motion in physics
  • Explore advanced problems involving multiple forces and inclines
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Students studying physics, particularly those focusing on mechanics and inclined plane problems, as well as educators seeking to clarify concepts of acceleration and friction.

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Homework Statement


3.00-kg block starts from rest at the top of a 30.0° incline and slides a distance of 2.00 m down the incline in 1.50 s. Find (a) the magnitude of the acceler- ation of the block, (b) the coefficient of kinetic friction between block and plane, (c) the friction force acting on the block, and (d) the speed of the block after it has slid 2.00 m.

Homework Equations

The Attempt at a Solution


a = 1.78 m.s2

(B) fk - mgsin@ = ma
Ukmgcos@ - mgsin@ = ma
Ukgcos@ -gsin@ = a
Uk= (a+ gsin@)/gcos@
Uk = 0.787
 
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Not getting the correct answer where am I going wrong?
 
You have a sign issue with the directions of the vector components. Draw an FBD that shows the directions of the vectors involved. Include the acceleration vector so that your choice of coordinate system is clear (so that the signs you assign to the force vectors when you write your equations match your choice of + direction for the acceleration).
 
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Oh yes its suppost to be mgsin@ -fk
 
But i still get the same eqn
 
Ab17 said:
But i still get the same eqn
Signs should change in your equation.
 
Ya I see it now. I made such a stupid mistake
 

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