Block released from spring slides up a ramp

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SUMMARY

The discussion focuses on a physics problem involving a block released from a spring that slides up a ramp. The user successfully calculated the block's velocity after leaving the spring as 3.553 m/s and addressed the effects of friction and gravity on the block's motion. The coefficient of friction was determined to be 0.200, leading to a calculated force of kinetic friction (Fk) of 6.178 N and a gravitational force (Fg) of 24.134 N. Ultimately, the user derived the acceleration to be 7.578 m/s² and calculated the distance traveled up the ramp to be approximately 0.833 meters.

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[SOLVED] Block released from spring slides up a ramp

Homework Statement


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Homework Equations


I'm thinking conservation of energy:
K1+U1+WOther=K2+U2
But really I'm not quite sure where to start here.

The Attempt at a Solution


So far, I've calculated the velocity of the block after it leaves the spring, before it hits the ramp and I get that to be 3.553 m/s2. What is tripping me up here is the coefficient of friction, and how to apply that to the block as it travels up the ramp. If I turn the coordinate system so that the x-axis is parallel to the ramp, then we can figure the x component of the velocity to be 3.553*Cos(38) I believe, but I'm not sure if that is useful to me or not.

I think if I could get some confirmation on which direction to take with this that would be very helpful. Thanks!
 
Last edited:
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Of course I figured it out after asking.

First I figured out that the Fk = n*.200, or cos(38)*(9.8)*(4)*(.200) = 6.178.

Next I figured out the force due to gravity, Fg = sin(38)*(9.8)*(4) = 24.134.

Add the two together and divide by mass (4kg) to get acceleration of 7.578.

Plug that into vf2 = vi2 + 2ad to get d = .833 or so. Sorry to bother everyone!
 

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