Block released from spring slides up a ramp

  • Thread starter Wint
  • Start date
  • #1
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[SOLVED] Block released from spring slides up a ramp

Homework Statement


fada240b6cd911d42a59c5a7d7ddd12d.png



Homework Equations


I'm thinking conservation of energy:
K1+U1+WOther=K2+U2
But really I'm not quite sure where to start here.

The Attempt at a Solution


So far, I've calculated the velocity of the block after it leaves the spring, before it hits the ramp and I get that to be 3.553 m/s2. What is tripping me up here is the coefficient of friction, and how to apply that to the block as it travels up the ramp. If I turn the coordinate system so that the x axis is parallel to the ramp, then we can figure the x component of the velocity to be 3.553*Cos(38) I believe, but I'm not sure if that is useful to me or not.

I think if I could get some confirmation on which direction to take with this that would be very helpful. Thanks!
 
Last edited:

Answers and Replies

  • #2
5
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Of course I figured it out after asking.

First I figured out that the Fk = n*.200, or cos(38)*(9.8)*(4)*(.200) = 6.178.

Next I figured out the force due to gravity, Fg = sin(38)*(9.8)*(4) = 24.134.

Add the two together and divide by mass (4kg) to get acceleration of 7.578.

Plug that in to vf2 = vi2 + 2ad to get d = .833 or so. Sorry to bother everyone!
 

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