Blocks on a slant(with friction)

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SUMMARY

The discussion focuses on analyzing a system of three blocks on a frictionless incline subjected to an external force F. Participants emphasize the importance of drawing free body diagrams for each block to apply Newton's 2nd law effectively. The correct formula for acceleration is established as a = [(g*sin(angle)) - (mu*g*cos(angle))] / (m1 + m2 + m3), although it requires clarification regarding the inclusion of force F. Additionally, the net force on each block and the contact forces between them are critical components of the analysis.

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  • Understanding of Newton's 2nd law of motion
  • Knowledge of free body diagram construction
  • Familiarity with forces on inclined planes
  • Basic concepts of friction and its coefficients
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rphmy
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This is the problem:

Three blocks on a frictionless incline are in contact with each other as shown in the following figure. A force F is applied to block 1 (mass m1), so the whole system moves up the incline.
a) Draw a free body diagram for each block.
b) Determine the acceleration of the system.
c) Determine the net force on each block.
d) What is the force of contact that each block exerts on its neighbor?

I can draw the free body diagram

I tried to determine the acceleration by saying

a=[(g*sin(angle))-(mu*g*cos(angle))]/[(m1+m2+m3)]

I think Fnet= Fp-Ffr

I also think the Fcontact=Fp*number of sides in contact with another block


Please any help would be much appreciated3
 
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rphmy said:
I can draw the free body diagram
Use that to apply Newton's 2nd law to each block.

I tried to determine the acceleration by saying

a=[(g*sin(angle))-(mu*g*cos(angle))]/[(m1+m2+m3)]
Where does this come from? Note that this equation has friction and leaves out the force F. It doesn't even have the right dimensions.

Apply Newton's 2nd law to each block separately. You can also apply it to all three blocks considered as a single system.
 

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