Bode Plots & High Pass, Low Pass, Band Stop and Pass Frequen

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SUMMARY

The discussion centers on the analysis of the transfer function H(s) = 1/(s+1)^2, specifically regarding its poles, zeros, and filter type. The participant correctly identifies that there are no zeros and two poles at s = -1. Additionally, the participant concludes that the filter exhibits a Low Pass response, as the magnitude approaches 1 when s approaches 0 and approaches 0 as s approaches infinity. This confirms the filter's behavior in allowing low frequencies to pass with minimal attenuation.

PREREQUISITES
  • Understanding of transfer functions in control systems
  • Familiarity with Bode plots and frequency response analysis
  • Knowledge of poles and zeros in system dynamics
  • Basic concepts of filter types: Low Pass, High Pass, Band Stop, Band Pass
NEXT STEPS
  • Study the derivation and implications of transfer functions in control theory
  • Learn how to construct and interpret Bode plots for various filter types
  • Explore the mathematical analysis of poles and zeros in system stability
  • Investigate the characteristics and applications of Low Pass filters in signal processing
USEFUL FOR

Electrical engineers, control system designers, and students studying signal processing who seek to deepen their understanding of filter design and frequency response analysis.

libnitz
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Homework Statement


Hi,

I just need some confirmation on 3 questions

H(s) = 1/(s+1)^2

1. I was asked to calculate the poles and zeros. I believe
zeros: none
poles: 2 (or p1,2) = -1

2. I was also asked to calculate the slope of the magnitude response was w -> 0
Here is my sketched graph

2016-02-20 20.17.13.jpg


From my pic, it shows that as w -> 0, H(s) -> 0.3. What type of filter response does this network exhibit.
I believe it will be a Low Pass because as

s->0, H(s) -> 1 and as s-> infinity, H(s) -> 0?

Does this reasoning make it a low pass filter, high pass, band stop or band pass?

Any help is appreciated
 
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According to your graph, what frequencies pass thru with the least attenuation?
 
Your Bode plot is good, and I can only second TomG's rhetorical question.
 

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