Bonding force of an optical electron and the nucleus of ion Cr3+

[gmentat]

Does anybody know how to find bonding force of an optical electron and the nucleus of ion Cr3+ (in pink ruby during normal and excited states (excitement of light))?

And also how to find the magnetic moment of the same electron during EPR (during excitement by a radiowave)? Condition of the resonance is: Intensity = 3.6 kGs and Frequency = 9.4 GHz (in normal and excited states).

Thanks for any suggestions!

 

[alxm]

The http://physics.nist.gov/PhysRefData/ASD/index.html" .

 

[gmentat]

Thanks for the link alxm. Can you give a clue how to find this value in the database? I'm not a physicist...

 

[alxm]

Well you enter "Cr III" and you get your spectral lines, or levels, depending on which database you look in. I believe it has relative g-factors as well.

The magnetic moment is always the same ($$\mu_B$$), it's the http://en.wikipedia.org/wiki/Landé_g-factor" that differs between levels/atoms. Given your g-factor, field strength and frequency, you have:
$$h\nu = g_\mathrm{e} \mu_B B_\mathrm{eff} = g_\mathrm{e} \mu_B B_0 (1 - \sigma)$$

Where $$B_{eff}$$ is the effective field, since the atom's environment (chemical bonds, if it's in a molecule, etc) is going to influence the field, which you can also express with the number $$\sigma$$. (If it didn't change with environment, EPR wouldn't be much use in analyzing chemical structure)

You might have to look into the literature to find relevant values for your g-factors, etc.