Finding Tension and Forces in a Cable-Supported Sign System

[agadag]

Homework Statement

A sign is supported by a uniform horizontal boom of length 3.00 m and weight 80.0 N. A cable, inclined at an angle of 35 with the boom, is attached at a distance of 2.38 m from the hinge in the wall (see figure below). The weight of the sign is 120 N. What is the tension in the cable and what are the horizontal and vertical forces Fx and Fy exerted on the boom by the hinge?

Homework Equations

I had 3 equations:
fx =Tcos 35
fy = 180+120-Tsin 35
Torque = Tsin 35 (2.38)-200(1.5)
solved for torque n got ...17.826...which is far from accurate! PLEASE HELP!

The Attempt at a Solution

Im sooooooo lost...pic attached!

 

[tiny-tim]

I had 3 equations:
fx =Tcos 35
fy = 180+120-Tsin 35
Torque = Tsin 35 (2.38)-200(1.5)
solved for torque n got ...17.826...which is far from accurate! PLEASE HELP!

Hi agadag!

(your fy should start 80, but I expect that's a typo?)

Your 200(1.5) is wrong …

you must find the moments (torques) of each weight separately.

 

[agadag]

yup that was a typo.
sooo what ur saying is..in order to find Torque:
Torque = Tsin 35(2.38) - [80(1.5) + 120(3)]
480 = T sin 35(2.38)
T = 350!
Thankyou!