Boundary conditions - Fresnel equations

Click For Summary
SUMMARY

The discussion centers on the boundary conditions of the Fresnel equations, specifically the parallel component of the electric field (E-Field) at the interface of two media. It is established that for the parallel components, Maxwell's equations dictate that E_{1t} = E_{2t}, and the relationship E_{it} + E_{rt} = E_{tt} holds true. The conversation clarifies that the Fresnel equations are derived under the assumption of infinite plane waves, which simplifies the analysis by treating waves as continuous electromagnetic fields rather than discrete pulses. This approach allows for the decomposition of complex light pulses into monochromatic components for easier application of the Fresnel equations.

PREREQUISITES
  • Understanding of Maxwell's equations
  • Familiarity with electromagnetic wave propagation
  • Knowledge of boundary conditions in optics
  • Experience with wave decomposition techniques
NEXT STEPS
  • Study the derivation of the Fresnel equations in detail
  • Learn about the decomposition of light pulses into frequency components
  • Explore applications of the Fresnel equations in optical systems
  • Investigate the differences between plane waves and pulsed laser beams
USEFUL FOR

Physicists, optical engineers, and students studying electromagnetism or wave optics who seek to deepen their understanding of the Fresnel equations and their applications in various optical scenarios.

spookyfw
Messages
24
Reaction score
0
Hello,
whenever I come to the derivation of the Fresnel equations I get stuck on the boundary condition for the component of the E-Field that is parallel to the surface.

I know for the parallel components Maxwell dictates that:

E_{1t} = E_{2t}.

For the parallel incoming light field component E_{it}, the reflected component E_{rt} and the refracted one E_{tt} it holds that:

E_{it} + E_{rt} = E_{tt}.

I always think about time though. I have the sequence in my head: ray coming in and then we have the refracted and reflected beam. Does that not apply because we just assume, that everything is happening at once?

Would be very nice if something could shed some light on this. Thank you very much in advance :) and have a good one,
spookyfw
 
Science news on Phys.org
The way the Fresnel equations problem is set up, we are dealing with infinite plane waves that have always been propagating, always reflecting, and always transmitting (this makes the math easier). There is no moment of reflection. We are not dealing with pencil-thin beams of laser-pulsed waves. That problem is much harder. In the Fresnel equations approach, we are treating the waves as extended electromagnetic fields that must match up at boundaries, rather than balls bouncing around. The reason this approach is useful is because you can represent any beam as a sum of monochromatic plane waves. For instance, to deal with a pulse of light (what you seem to have in your head), you would decompose it into its frequency components, apply the Fresnel equations or whatever else to each component, then sum the results to get your final solution.
 
Sorry for not replying earlier. Thank you very much for your reply :)! It is clear now.

Have a good one,
spookyfw
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 2 ·
Replies
2
Views
9K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
6K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K