MHB Bounded Output Bounded Input BIBO

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To determine if an LTI system is BIBO stable, one must analyze the poles of its transfer function. For the given transfer function H(s) = (s - 2)/((s + 2)(s + 1)(s - 1)), the stability condition states that all poles must have negative real parts. In this case, the pole at s = 1 has a positive real part, indicating that the system is unstable. Therefore, the system is not BIBO stable due to the presence of this pole. Understanding pole locations is crucial for assessing BIBO stability in LTI systems.
Dustinsfl
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Can some show me how we show a LTI system is BIBO? I read the definition but it didn't help.

For example, how would we show if
\[
H(s) = \frac{s - 2}{(s + 2)(s + 1)(s - 1)}
\]
is BIBO stable or unstable?
 
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dwsmith said:
Can some show me how we show a LTI system is BIBO? I read the definition but it didn't help.

For example, how would we show if
\[
H(s) = \frac{s - 2}{(s + 2)(s + 1)(s - 1)}
\]
is BIBO stable or unstable?

The stability condition requires that the Transfer Function has all poles with negative real part... one of poles is in s=1 so that...

Kind regards

$\chi$ $\sigma$
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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