MHB Bounded Output Bounded Input BIBO

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To determine if an LTI system is BIBO stable, one must analyze the poles of its transfer function. For the given transfer function H(s) = (s - 2)/((s + 2)(s + 1)(s - 1)), the stability condition states that all poles must have negative real parts. In this case, the pole at s = 1 has a positive real part, indicating that the system is unstable. Therefore, the system is not BIBO stable due to the presence of this pole. Understanding pole locations is crucial for assessing BIBO stability in LTI systems.
Dustinsfl
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Can some show me how we show a LTI system is BIBO? I read the definition but it didn't help.

For example, how would we show if
\[
H(s) = \frac{s - 2}{(s + 2)(s + 1)(s - 1)}
\]
is BIBO stable or unstable?
 
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dwsmith said:
Can some show me how we show a LTI system is BIBO? I read the definition but it didn't help.

For example, how would we show if
\[
H(s) = \frac{s - 2}{(s + 2)(s + 1)(s - 1)}
\]
is BIBO stable or unstable?

The stability condition requires that the Transfer Function has all poles with negative real part... one of poles is in s=1 so that...

Kind regards

$\chi$ $\sigma$
 
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