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## Homework Statement

A 2kg box is at the top of an inclined plane that is 10m long. The inclined plane makes an angle of 30° with the ground. The μk of the ramp is 0.36 and the μk of the flat ground at the end of the ramp is 0.50. How far does the box travel along the flat ground until it stops?

I'm not quite sure what to do after finding the acceleration, but I think you need to find the final velocity of the box when it finishes going down the ramp? I can't seem to figure out what to do past this point, so any help would be greatly appreciated. Thanks for your time.

## Homework Equations

## The Attempt at a Solution

1. Fg=mg

Fg=2kg(10m/s^2)

Fg=20N

2.Fgx=mgsinθ

Fgx=2kg(10m/s^2)sin30°

Fgx=10 N

3. Fgy=mgcosθ

Fgy=2kg(10m/s^2)cos30°

Fgy=17.32N

4.a=g(sinθ-μkcosθ)

a=10m/s^2(sin30°-0.36cos30°)

a=1.88m/s^2

5.vf^2=vi^2 +2ad

Vf^2=(0m/s)^2 +2(1.88m/s^2)(10m)

Vf=6.13m/s