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## Homework Statement

The resistor R in the above figure has a resistance of 21.7 Ω.

a) Find the current in the resistor R. (Enter a positive number for a current up and to the right, and negative for down and to the left.

b) Find the current in the 10-Ω resistor. (Enter a positive number for a downward current, negative for an upward current.)

https://wug-s.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?cc/Knox/phys130a/spring/homework/10/03/P26_29.jpg [Broken]

## Homework Equations

Current Leaving Battery= Voltage/total resistance

V=IR (Ohm's Law)

## The Attempt at a Solution

Well, I tried to find the total resistance and ended up with 2.692 (I'm not sure this is right because of how the circuit is set up), then I divided the voltage by this, and got 2.228 as the current from the battery. Then I used this current to find the voltage at the point after the resistor R with Ohm's Law, which gives me 60.378V. I use the voltage drop between the points (which is -54.3788) and the resistance of the resistor to find the current (from Ohm's Law again), this gives me -2.007. This is wrong, as I expected. I'm not sure how to go about doing this. :/

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