Brightness of Light Bulbs Ranking Task

AI Thread Summary
The discussion focuses on ranking five identical light bulbs (A through E) based on brightness in a circuit with an ideal battery. The user concludes that bulb C is the brightest, followed by bulbs A and B, which are equivalent, and then bulbs D and E, which are also equivalent. The reasoning involves understanding that while all bulbs have the same resistance, the voltage across bulb C is higher due to its configuration, leading to greater power output. The relationship between current, voltage, and power is emphasized, clarifying that higher voltage results in increased brightness despite identical resistances. The conclusion highlights the importance of circuit configuration in determining bulb brightness.
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Homework Statement


Consider a circuit containing five identical light bulbs and an ideal battery. Assume that the resistance of each light bulb remains constant. Rank the bulbs (A through E) based on their brightness.
Rank from brightest to dimmest. To rank items as equivalent, overlap them.
y09pc.jpg


Homework Equations



V=IR, junction law and loop law

The Attempt at a Solution



i use that fact that more resistance means that less current flow by looking at the pic the current in A&B are the same, but the current in C is greater than in D&E where current in D&E are same b/c of series. there for conclude that C>(A=B)>(D=E)

can any 1 tell me if this is right please!
 
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its right
 
If anyone didn't mind me asking, I was wondering WHY Bulb C has less resistance compared to Bulb A or B?
 
It doesn't have less resistance, all resistances are the same. It has more voltage because the equivalent resistance of RcRdRe is greater than that of RaRb. If you link brightness to power (P=I*V) and Rab has the same current as Rcde, then because the voltage is higher Rc has more power.
 

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