- #1
Frank-95
- 52
- 1
Hi all.
I would like to ask some explanation regarding how to obtain L and C values for a butterworth filter using the first Cauer topology. I will consider a normalized low pass filter.
(Link added by Mentor)
https://en.wikipedia.org/wiki/Butterworth_filter
What I don't understand is this: how to pass from transfer function to L and C values?
For example: let's consider a second order filter, with 0 dB gain at DC (for simplicity). I have:
|H(jω)|2 = 1 / [1 + (ω/ωc)2n] ⇒ H(s)H(-s) = 1 /[1 + (-s2/ωc2)n]
We find poles by putting the deniminator equal to 0. Hence it yields:
sk = jωcej(2k - 1)π/(2n)
For n = 2 and k = 1, 2
s1 = jωcejπ/4
s2 = jωcej3π/4
I thus have:
H(s) = ωc / [(s - s1) (s - s2)]
As shown also on wikipedia.
What I don't understand now is this: how can I calculate from here the values of capacitors and inductors of the LC ladder. There are formulas at wikipedia but they don't explain how they are obtained.
Any tip?
Thank you
I would like to ask some explanation regarding how to obtain L and C values for a butterworth filter using the first Cauer topology. I will consider a normalized low pass filter.
(Link added by Mentor)
https://en.wikipedia.org/wiki/Butterworth_filter
What I don't understand is this: how to pass from transfer function to L and C values?
For example: let's consider a second order filter, with 0 dB gain at DC (for simplicity). I have:
|H(jω)|2 = 1 / [1 + (ω/ωc)2n] ⇒ H(s)H(-s) = 1 /[1 + (-s2/ωc2)n]
We find poles by putting the deniminator equal to 0. Hence it yields:
sk = jωcej(2k - 1)π/(2n)
For n = 2 and k = 1, 2
s1 = jωcejπ/4
s2 = jωcej3π/4
I thus have:
H(s) = ωc / [(s - s1) (s - s2)]
As shown also on wikipedia.
What I don't understand now is this: how can I calculate from here the values of capacitors and inductors of the LC ladder. There are formulas at wikipedia but they don't explain how they are obtained.
Any tip?
Thank you
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