C^2 in Lorentz transformations and special relativity.

In summary: Wigner's "unreasonable effectiveness of mathematics in the natural sciences".Maybe the "intuitive" will be the day when we finally understand how to describe a single photon or an electron traveling from emitter to absorber without the need of probability distributions... or of "collapse of a wave function"...In summary, c^2 appears frequently in special relativity due to the choice of units, specifically the units of distance and time. This is due to the Pythagorean theorem, which relates the lengths of two systems using a right triangle. In (1+1)-Minkowski spacetime, c^2 arises due to the different choice of units and the square-interval posted by JesseM. However, it is still the same
  • #1
accidentprone
17
0
c^2 occurs frequently in special relativity: in the Lorentz transformations, in forumlas for the interval, relativistic energy, and others too. Is there an intuitive reason for the high occurence of c^2?
 
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  • #2
Well, I can't really say this means much, but you're looking at velocity squares, [tex]ds^2[/tex], etc etc, so the [tex]c^2[/tex] makes sense I suppose.
 
  • #3
Yeah, I think most or all of those equations involving c^2 can be derived from the equation for the invariant spacetime interval which can be written as [tex]d\tau^2 = \sqrt{dt^2 - (1/c^2)dx^2} = dt \sqrt{1 - v^2/c^2}[/tex], and which plays a role in spacetime analogous to the role of the invariant spatial distance in 2D space given by the Pythagorean theorem as [tex]\sqrt{dx^2 + dy^2}[/tex] (see [post=2972720]this post[/post] for more on the geometric analogy)
 
  • #4
The short answer is "c^2 appears because of the choice of units (that distances and times are measured in different units)". JesseM's post gives more details.
 
  • #5
If you were to measure heights in inches and lateral distances in feet, then work out the height and width of a rectangle containing a rotated yard stick in terms of its slope (in units of feet per inch) you'd get a bunch of c=12 in/ft factors in your formulas:

[tex] z = z_0 \cos(\theta) + c\cdot x_0\sin(\theta)[/tex]

[tex] x = -c^{-1}\cdot z_0 \sin(\theta) +x_0\cos(\theta)[/tex]

[tex] m = \frac{z}{x}= c\cdot \tan(\theta)[/tex]

so
Letting
[tex]\gamma = \cos(\theta) = \frac{1}{\sqrt{1+\tan^2(\theta)}} =\frac{1}{\sqrt{1+(m/c)^2}}[/tex]
and
[tex] \sin(\theta) = \cos(\theta)\tan(\theta)=\gamma m/c[/tex]
you have:
[tex] z = \gamma (z_0 + m x_0)[/tex]
[tex] x = \gamma (x_0 - (m/c^2)z_0)[/tex]

Now replace (z,x) with (x,t) and the circle trig with hyperbolic trig...
[edit: and replace m with v ]
(above was typed in a rush, check for errors.)
 
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  • #6
accidentprone said:
c^2 occurs frequently in special relativity: in the Lorentz transformations, in forumlas for the interval, relativistic energy, and others too. Is there an intuitive reason for the high occurence of c^2?

Good question. As JesseM pointed out already, it's due to the Pythagorean theorem. ...

See this post, and in particularly note the 1st equation which defines lengths in one system using the Pythagorean theorem. It also explains Einstein's kinematic model setup, which should help make all this clearer to you ...


Pythagoras' theorem is used because the lightpath (ct) is related to an observer moving along +x at v (so vt), and the systems are related by the vertical path y=Y which forms a right triangle. Since Pythagorus' theorem applies, c2 arises.

HYP2 = ADJ2 + OPP2

That 1st Eqn of the referenced link above, is this ...

(ct)2 = (vt)2+y2 <- 1st EQN​

so ...

y2 = (ct)2-(vt)2
y2 = t2(c2-v2)
y2 = (ct)2(1-v2/c2)
y = ct(1-v2/c2)1/2
y/c = t(1-v2/c2)1/2

However, since no length contractions exist wrt axes orthogonal to the direction of motion (motion is along x, x being colinear with X), then y=Y, Y being an axis of the moving system that appears always parallel to y, so ...

Y/c = t(1-v2/c2)1/2

But in the moving system, from its own POV as stationary, Y = cTau (since light is isotropic), so ...

cTau/c = t(1-v2/c2)1/2
Tau = t(1-v2/c2)1/2

This equation relates the time readouts of 2 clocks that were once co-located prior at their origins (of systems x,y,z,t and X,Y,Z,Tau).

That said, the c2 that pops up often in SR is the direct result of Pythagoras' theorem relating lengths of the 2 systems using a right traingle as seen in EQN 1 above. We often see (v/c)2 as well, mainly because we like to reduce equations to their simplest form, or a form that presents the most inherent meaning at a glance ... eg Tau = t(1-(v/c)2)1/2

GrayGhost
 
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  • #7
GrayGhost said:
Good question. As JesseM pointed out already, it's due to the Pythagorean theorem. ...

...snip...

That said, the c2 that pops up often in SR is the direct result of Pythagoras' theorem relating lengths of the 2 systems using a right traingle as seen in EQN 1 above. We often see (v/c)2 as well, mainly because we like to reduce equations to their simplest form, or a form that presents the most inherent meaning at a glance ... eg Tau = t(1-(v/c)2)1/2

GrayGhost

c^2 already pops up in (1+1)-Minowski spacetime... due the different choice of units (as mentioned earlier) and the square-interval posted by JesseM. Since the [Euclidean Space] Pythagorean Theorem doesn't play any role in (1+1)-Minkowski spacetime, it can't be the ultimate source of the c^2 in Special Relativity.

If there's a constant that arises from the [Euclidean] Pythagorean Theorem, it's pi.
 
  • #8
robphy said:
c^2 already pops up in (1+1)-Minowski spacetime... due the different choice of units (as mentioned earlier) and the square-interval posted by JesseM. Since the [Euclidean Space] Pythagorean Theorem doesn't play any role in (1+1)-Minkowski spacetime, it can't be the ultimate source of the c^2 in Special Relativity.

If there's a constant that arises from the [Euclidean] Pythagorean Theorem, it's pi.

The reason c2 pops up in Minkowski spacetime, is for the reason I stated. It's all the same.

GrayGhost
 
  • #9
accidentprone said:
c^2 occurs frequently in special relativity: in the Lorentz transformations, in forumlas for the interval, relativistic energy, and others too. Is there an intuitive reason for the high occurence of c^2?

Minkowski spacetime is defined by the line element

ds2 = -c2 dt2 + dx2 + dy2 + dz2

c is converting units of time into units of distance.
 
  • #10
Maybe it will become more "intuitive" when we have relativity and quantum mechanics fully unified.

That differing velocities may alter our measure of distances, elapsed times, and even different orderings of events is one CRAZY notion...hardly "intuitive" yet so far inescapable.

Seems like we have moved from the Galilean transformation of Newtonian physics, to the Lorentz transformations which Einstein incorporated into relativity... then the more general Poincaré group...(was that later?? I'm not sure) ...In fact it's not even "intuitive" that our man made math should even describe so much of what we observe. Talk about "coincidence".
 
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  • #11
accidentprone said:
c^2 occurs frequently in special relativity: in the Lorentz transformations, in forumlas for the interval, relativistic energy, and others too. Is there an intuitive reason for the high occurence of c^2?

More important is v and not c. Without v^2 frame with +v wouldn't be equivalent to that with -v
 

1. What is the significance of C^2 in Lorentz transformations and special relativity?

The speed of light, denoted by c, is a fundamental constant in physics. It plays a crucial role in the theory of special relativity, which describes how the laws of physics behave in different reference frames moving at constant velocities. The square of the speed of light (c^2) appears in the famous equation E=mc^2, which relates energy (E) and mass (m). It is also a factor in the Lorentz transformation equations, which describe how measurements of time and space differ between observers in different frames of reference.

2. Why is the speed of light considered to be the maximum speed in the universe?

According to the theory of special relativity, the speed of light is an absolute speed limit in the universe. This means that no object or information can travel faster than c. This is due to the fact that as an object approaches the speed of light, its mass increases infinitely and the energy required to accelerate it further also approaches infinity. Therefore, it is physically impossible for anything to reach or exceed the speed of light.

3. How does the square of the speed of light affect the concept of time dilation?

One of the consequences of special relativity is time dilation, which states that time passes slower for a moving object relative to a stationary observer. The amount of time dilation is directly proportional to the velocity of the object, but also inversely proportional to the square root of 1-c^2/v^2, where v is the velocity of the object. This means that as an object approaches the speed of light, time dilation becomes more significant and time appears to slow down dramatically for the moving object.

4. Can the square of the speed of light be used to calculate the mass of an object at high velocities?

Yes, the famous equation E=mc^2 can be rearranged to calculate the mass (m) of an object in terms of its energy (E) and the speed of light (c). This is known as the mass-energy equivalence formula and it shows that mass and energy are interchangeable. As an object's velocity approaches the speed of light, its mass increases significantly due to the presence of the c^2 term in the equation.

5. How does the square of the speed of light affect the concept of length contraction?

Another consequence of special relativity is length contraction, which states that a moving object appears shorter in the direction of motion when measured by a stationary observer. The amount of length contraction is also directly proportional to the velocity of the object, but inversely proportional to the square root of 1-c^2/v^2. This means that as an object approaches the speed of light, length contraction becomes more significant and the object appears to be compressed in the direction of motion.

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