- #1

White Ink

- 19

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## Homework Statement

Write a function that prompts the user to enter a year and that returns a 1 if the entered year is a leap year, and a 0 otherwise.

A year is a leap year if it is divisible by 4.

In general, a year is not a leap year if it is divisible by 100, unless of course it is divisible by 400.

## The Attempt at a Solution

I have done this much and when I test my program, it seems to return a value of 1 no matter what year I enter. I'm pretty awful at programming and I was wondering if anyone could spot where my mistake is.

*#include <iostream>*

using namespace std;

bool leap(int) {

int n;

bool b;

if (n%4==0) { b=true; } // if n is divisible by 4, it is a leap year

else if (n%100==0) {

if (n%400==0) { b=true; }

else { b=false; }

} // if n is divisible by 100, check if it is divisible by 400, if it is, it is a leap year

else { b=false; } // if n is not divisible by 4 (=> it is not divisible by 400 either), then it is not a leap year

return b;

}

int main () {

int n;

cout << "Please enter a year: " << '\n';

cin >> n;

cout << leap(n);

}

using namespace std;

bool leap(int) {

int n;

bool b;

if (n%4==0) { b=true; } // if n is divisible by 4, it is a leap year

else if (n%100==0) {

if (n%400==0) { b=true; }

else { b=false; }

} // if n is divisible by 100, check if it is divisible by 400, if it is, it is a leap year

else { b=false; } // if n is not divisible by 4 (=> it is not divisible by 400 either), then it is not a leap year

return b;

}

int main () {

int n;

cout << "Please enter a year: " << '\n';

cin >> n;

cout << leap(n);

}