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A solid lies between planes perpendicular to the xaxis at x=a and x=a for values of a>0 to be given below in parts (i) and (ii). In each case the crosssections perpendicular to the xaxis between these planes run from the semicircle y=√(a^2x^2) to the semicircle
y=√(a^2x^2).
If a=7 and the crosssections are equilateral triangles with bases in the xy plane, find a formula for the area A(x) of the crosssection at location x.
For the base i used 2*√(a^2x^2), for the height i used √(a^2x^2)/tan(30). so i get
(a^2x^2)/tan(30) as an answer, which is not right. what am i doing wrong i cant seem to figure it out.
i uploaded a picture of what the problem gave me if it helps.
THANKS!!!
y=√(a^2x^2).
If a=7 and the crosssections are equilateral triangles with bases in the xy plane, find a formula for the area A(x) of the crosssection at location x.
For the base i used 2*√(a^2x^2), for the height i used √(a^2x^2)/tan(30). so i get
(a^2x^2)/tan(30) as an answer, which is not right. what am i doing wrong i cant seem to figure it out.
i uploaded a picture of what the problem gave me if it helps.
THANKS!!!
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