1. The problem statement, all variables and given/known data Find a vector that has the same direction as the given vector but has length 6. ‹4, 2, -2› 2. Relevant equations L = ((x-i)^2+(y-j)^2+(z-k)^2)^.5 3. The attempt at a solution For some reason I am just stuck. I don't know how to start. I assume L = ((x-i)^2+(y-j)^2+(z-k)^2)^.5 becomes L = (x^2+y^2+z^2)^.5 because of the 2 points (0,0,0) and (x,y,z) but how does one find something with the length of 6 in 3 dimensions? All I really have is this 36=x^2+y^2+z^2 I guess I could eliminate z by finding an equation for a line on points (0,0,0) and (4,2,-2). I found that equation to be z=x-3y but after plugging that in it seems that I have 2 independent variables(x and y). How do I deal with this? Thanks!