Calc Angle of Rope Swing for 82kg Man, 1450kg Car

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    Angle Rope Swing
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Homework Help Overview

The problem involves calculating the angle from the vertical at which a man must begin to swing on a rope to achieve the same kinetic energy as a moving car. The scenario includes a rope length of 2.90 m, a mass of 82 kg for the man, and a car mass of 1450 kg moving at a specified speed.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of kinetic energy for both the man and the car, and the relationship between potential energy and height. There are questions about the correctness of the calculated angle and the setup of the triangle used in the calculations.

Discussion Status

Some participants are exploring the relationship between potential and kinetic energy, while others are questioning the assumptions made about the triangle's dimensions. There is an acknowledgment of a mistake in the previous calculations, and guidance is being offered to reconsider the triangle's sides.

Contextual Notes

Participants are working under the constraints of homework guidelines, which may limit the information they can share or the methods they can use. There is an emphasis on understanding the geometric relationships involved in the problem.

ganondorf29
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Homework Statement


The rope of a swing is 2.90 m long. Calculate the angle from the vertical at which a 82.0 kg man must begin to swing in order to have the same KE at the bottom as a 1450 kg car moving at 1.11 m/s (2.48 mph).



Homework Equations


k=(m*v^2) / 2
U = mgh


The Attempt at a Solution



I first found the kinetic energy of the car. 1/2*[(1450)*(1.11^2) = kcar. I found kcar to be 893.273 J. Than I used U=mgh to find the height the man must be to have the same amount of kinetic energy. Kcar = 82*9.8*h. I found the height to be 1.11m. Than I set up a triangle and tried cos^-1 = (1.11/2.9) to find theta. I got 67.5 deg, but that's wrong. Any suggestions?
 
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How do you know that's wrong? Do you have the answer? Is it 22.5?
 
ganondorf29 said:

Homework Statement


The rope of a swing is 2.90 m long. Calculate the angle from the vertical at which a 82.0 kg man must begin to swing in order to have the same KE at the bottom as a 1450 kg car moving at 1.11 m/s (2.48 mph).



Homework Equations


k=(m*v^2) / 2
U = mgh


The Attempt at a Solution



I first found the kinetic energy of the car. 1/2*[(1450)*(1.11^2) = kcar. I found kcar to be 893.273 J. Than I used U=mgh to find the height the man must be to have the same amount of kinetic energy. Kcar = 82*9.8*h. I found the height to be 1.11m. Than I set up a triangle and tried cos^-1 = (1.11/2.9) to find theta. I got 67.5 deg, but that's wrong. Any suggestions?
You're very nearly there, just one small mistake. Does his height really make up one of the sides of the triangle that you need?
 
Try again
 

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I understand what I did wrong now, but how do I apply that to fix them problem?
 
ganondorf29 said:
I understand what I did wrong now, but how do I apply that to fix them problem?
Well if the height isn't the adjacent side of the triangle, then what is? Look at the sketch that phyguy provided.
 
I am actually working on a problem very similar to this one and I found the height of the person, but I am stuck on how you find the angle. I looked at the image given in this thread but it was the same image I had already drawn out in my attempt at solving the problem. My thinking is that if the energy is conserved then at the bottom of the swing there would not be any potential energy, it would be all kinetic, implying that the height at the bottom of the swing would be zero. Therefore the adjacent side of the large triangle would be the length of the rope, but I am not sure how you find the hypotenuse of the triangle when you know the height and the length of the rope. I would appreciate help regarding this question, thanks!
 

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