Calc Rate Problem: At What Rate is Volume Increasing?

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Homework Help Overview

The discussion revolves around a calculus problem involving the relationship between pressure and volume of air expanding adiabatically, described by the equation PV^{1.4}=C. The original poster seeks to determine the rate of change of volume given specific values for pressure and volume, along with the rate of change of pressure.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need to differentiate the equation with respect to time to find the relationship between the rates of change of pressure and volume. There is confusion about the correct differentiation process and notation.

Discussion Status

Some participants have provided guidance on differentiating the equation and establishing a relationship between the rates of change. There is ongoing clarification regarding the correct application of calculus principles, but no consensus on the final solution has been reached.

Contextual Notes

Participants note the importance of treating pressure and volume as functions of time and the need to apply the correct differentiation techniques. The original poster has provided specific numerical values, but the discussion remains focused on the methodology rather than arriving at a definitive answer.

Okie
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hen air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equation PV^{1.4}=C where C is a constant. Suppose that at a certain instant the volume is 630 cubic centimeters and the pressure is 97 kPa and is decreasing at a rate of 7 kPa/minute. At what rate in cubic centimeters per minute is the volume increasing at this instant?

(Pa stands for Pascal -- it is equivalent to one Newton/(meter squared); kPa is a kiloPascal or 1000 Pascals. )

I think i start by doing (97)(630)^1.4 = 805097.5471 what is my next step? How do i solve this problem
 
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You can't start by putting numbers in--P and V are functions of time. Find a relationship between the rates of change (i.e., time derivatives) of P and V, and then solve for dV/dt.

Then you can put your numbers in.
 
I don't get it. So i differentiate pv^1.4 ?

so the answer would be 1.4pv' + v^1.4 ... would that be correct?
 
No. Both p and v are functions of t, so you need to differentiate with respect to t. I would recommend using d/dt (Leibniz) notation rather than ' (Newton) notation.

Start with your equation, PV1.4 = C, and differentiate both sides with respect to t. You should get another equation with P, dP/dt, V, and dV/dt. Solve that equation for dV/dt. Then you can find the value of dV/dt at the particular time in question.
 
Is this correct ?

dP/dt = -[P 1.4*V^.4 dV/dt]/[V^1.4]
 
That can be simplified but, yes, I think it is correct. I have trouble reading the formula like that so...

\frac{dP}{dt} = \frac{-1.4P\frac{dV}{dt}}{V}

Now that you have an equation that relates the rates, the problem is figuring out what these values are from the problem. You solved for dP/dt and I'm not sure why, but it stills works. The problem asks for the rate at which volume is changing, and it gives you a volume, pressure, and a rate at which pressure is changing. Your new equation has 4 variables, Pressure, Volume, the rate at which Pressure changes, and the rate at which Volume changes. Plug in your known variables and solve the problem.
 
Thank you i got the answer . :smile:
 
The answer is 32.47422681
 

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