Calc Required Torque & RPM for Automotive App

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SUMMARY

This discussion focuses on calculating the required torque and RPM for moving a stationary vehicle weighing 12,990 kg with an engine displacement of 3,455 cc. Key inputs include gear ratios, tire radius, and engine torque measurements of 230 Nm at 1,000 RPM and 241 Nm at 1,200 RPM. The conversation highlights that the torque needed to initiate movement depends on the friction of moving parts and suggests using a spring scale to measure the torque at the wheels. Additionally, it emphasizes that drivetrain losses can be significant, potentially around 30%.

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  • Understanding of vehicle dynamics and torque calculations
  • Familiarity with gear ratios and their impact on torque
  • Knowledge of drivetrain efficiency and power loss
  • Basic principles of friction and its effect on stationary objects
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  • Research "Calculating Torque for Vehicle Movement" techniques
  • Learn about "Drivetrain Efficiency and Power Loss" in automotive applications
  • Explore methods for measuring torque using a "Spring Scale" in practical scenarios
  • Study "Gear Ratio Calculations" and their effects on vehicle performance
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Automotive engineers, vehicle performance analysts, and anyone involved in the design or optimization of vehicle torque and drivetrain systems.

Rob
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Hello
I am working on vehicle, for which i need to calculate following things

1. Required torque (Nm) to move vehicle from stationary position?
2. RPM of the engine at the time of torque mentioned in point number 1?

Available Input:
1. Vechile Weight(kg) - 4300
2. Engine Displacement - 3455
3. Gross Vechile Weight(kg) - 12990
4. Tyre Raduis (m) - 0.464
5. Gear Ratio 1st - 7.600
6. Gear Ratio 2nd - 3.7
7. Final gear Ratio - 6.142
8. Engine Max. Te(Nm) - 315 @ 1625RPM
9. Engine Torque = 230 Nm @ 1000 rpm , 241 Nm @ 1200 rpm (Actual Measurement)

Thanks,
 
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Copied from your the identical question in this thread https://www.physicsforums.com/threads/calculate-motor-torque-requide-to-drive-a-cart.772433/

Please don't double up posts, it makes the forum messy.

billy_joule said:
"241 Nm @ 1200 rpm"

That gives a power of under 30kW, a third of the power of my last motorbike. Good luck shifting a 12 tonne vehicle with that. It's possible but probably not wise.

As for your questions:

1. Depends on the friction of all moving parts.
2. Zero. If the vehicle is stationary, so is the motor (unless you use a clutch).

Rob said:
Thanks for help

We are using dry friction clutch
Vehicle stationary and engine is idling, but when i put vehicle on 1st gear at what point of Torque@RPM vehicle start moving?

When the torque applied by the motor is equal to the friction of all moving parts.
There's no easy way of calculating this. Easiest way is probably to pull the stationary vehicle with a spring scale - the reading when the truck begins to move can be used to calculate the torque at the wheels required to move. Of course that ignores all the torque losses between the motor and the wheels which could be around 30%, it'll depend on the efficiency and condition of your drive train, this article is a good intro to drivetrain losses:

http://www.modified.com/tech/modp-1005-drivetrain-power-loss/
 

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