Calculate a volume using the washer method

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SUMMARY

The discussion focuses on calculating the volume of a solid of revolution using the washer method for the functions y=x^2+1 and y=9-x^2. The intersection points were determined to be x=±2, leading to the outer radius of 10-x^2 and inner radius of 2+x^2. The area was calculated as 24π(4-x^2), and the final volume was confirmed to be 256π through integration from 0 to 2. Verification of the solution using both the washer and shell methods is recommended.

PREREQUISITES
  • Understanding of the washer method for volume calculation
  • Knowledge of integration techniques
  • Familiarity with finding intersection points of functions
  • Basic algebra for manipulating polynomial equations
NEXT STEPS
  • Study the washer method in detail, focusing on its application in volume calculations
  • Learn about integration techniques, specifically definite integrals
  • Explore the shell method for volume calculations as a comparative technique
  • Practice solving similar problems from Stewart's Calculus, particularly Chapter 6
USEFUL FOR

Students studying calculus, particularly those focusing on volume calculations of solids of revolution, as well as educators looking for problem-solving techniques in integration.

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Homework Statement



y=x^2+1
y=9-x^2
y=-1 rotate

Homework Equations





The Attempt at a Solution



intersection
x^2+1=9-x^2=>2x^2-8=0=>2(x^2-4)=0=>x=+-2
Washer method
outer radius = 1+9-x^2=10-x^2
inner radius = 1+x^2+1=2+x^2
Area=pi((10-x^2)^2-(2+x^2)^2)=pi(100-20x^2+x^4-4-4x^2-x^4)=pi(96-24x^2)=24pi(4-x^2)
by symatrey
V=48pi Integral( 4-x^2,x,0,2)=48pi[4x-x^3/3,0,2]=48pi(8-8/3)=48pi(24-8)/3=48pi*16/3=256pi

if you can try and solve to verify please, or else if you have a membership to cramster this is problem 10 in the the chapter 6 review stewart 5e
 
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Yes, 256pi is right. You could always try the problem by both shell and washer method to check the answer.
 

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