Calculate Arc Length of Hypocycloid Function | Homework Help

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SUMMARY

The arc length of the hypocycloid defined by the parametric equations r(t) = cos(t)^3 i + sin(t)^3 j from t = 0 to t = 2 * Pi is calculated using the formula s = ∫√(x'^2 + y'^2) dt. The derivatives are x' = -3cos(t)^2*sin(t) and y' = 3sin(t)^2*cos(t), leading to the integral s = ∫3√(cos(t)^4*sin(t)^2 + sin(t)^4*cos(t)^2) dt. The correct evaluation yields an arc length of 6π, although there is a discrepancy with the Maple software output.

PREREQUISITES
  • Understanding of parametric equations
  • Knowledge of calculus, specifically integration techniques
  • Familiarity with derivatives and their applications in arc length calculations
  • Experience with mathematical software such as Maple for verification
NEXT STEPS
  • Review the derivation of arc length for parametric curves
  • Explore the properties of hypocycloids and their applications
  • Learn how to use Maple for symbolic integration and verification of results
  • Investigate common pitfalls in calculus involving radical simplifications
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Students studying calculus, mathematics educators, and anyone interested in the geometric properties of hypocycloids and their arc length calculations.

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Homework Statement


Find the arc length of r(t) = cos(t)^3 i + sin(t)^3 j
from t = 0 to t = 2 * Pi

It's a hypocycloid that's four cusped.

Homework Equations


[tex]s = \int\sqrt{x'^2 + y'^2}[/tex]


The Attempt at a Solution


x = cos(t)^3
y = sin(t)^3

x' = -3cos(t)^2*sin(t)
y' = 3sin(t)^2*cos(t)

[tex]\sqrt{x'^2 + y'^2}[/tex] = 3* [tex]\sqrt{cos(t)^4*sin(t)^2 + sin(t)^4*cos(t)^2}[/tex]

That simplifies to [tex]s = \int 3*\sqrt{1}[/tex]

So the answer is 6*Pi, but for some reason Maple throws out 6.
 
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The radical doesn't simplify to 1. Check that again.
 

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