Calculate Avg. Water Velocity in Pipe from Well

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Homework Help Overview

The original poster attempts to calculate the average velocity of water being pumped from a well into a storage tank through a pipe with a specified cross-sectional area. The problem involves converting units and applying relevant equations related to fluid dynamics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between volume, area, and velocity, with some suggesting formulas that relate these quantities. Questions arise regarding the interpretation of terms like "V/s" and the lack of information about the length of the water tube.

Discussion Status

Some participants have offered guidance on how to approach the calculation of average velocity, while others are clarifying terminology and questioning the assumptions made in the problem setup. Multiple interpretations of the terms and relationships involved are being explored.

Contextual Notes

The original poster notes a conversion of units and expresses uncertainty about the appropriate equations to use. There is also a mention of missing information regarding the length of the tube, which may affect the calculations.

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Homework Statement



Water is pumped into a storage tank from a well delivering 17.0 gallons of water in 29.0 seconds through a pipe of 1.00 in.^2 cross-sectional area. What is the average velocity of the water in the pipe as the water is pumped from the well?

A=1in^2

the answer should be in inches/second.


I converted 17gal./s. to 22m^3/s = 866.14in^3/s, but I'm not sure what equation i need to use to get started.

Some assistance getting started would be appreciated.

thanks
 
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Volume of water = area of cross section of pipe x length of the water tube.
Therefore V/s = Area x L/s
 
In February 1955, a paratrooper fell 370 m from an airplane without being able to open his chute but happened to land in snow, suffering only minor injuries. Assume that his speed at impact was 58 m/s (terminal speed), that his mass (including gear) was 85 kg, and that the force on him from the snow was at the survivable limit of 1.2 105 N.

(a) What is the minimum depth of snow that would have stopped him safely?

?m

(b) What is the magnitude of the impulse on him from the snow?


? kg·m/s

can some one HELP ME ON THIS PROBLEM?
 
I didn't understand rl.bhat's explanation. What's V/s? Also the length of tube is NOT given. Can someone explain please?
Thanks
 
v/s is velocity over displacement.
 
no volume/seconds
 
Average velocity = (Volume/Second)/Area
You have calculated volume of water. Time is given. Find the average velocity.
 
yup L/S is the velocity like how rl.bhat put it in the second post.
 

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