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Calculate capacitance of conductors

  1. Jul 25, 2012 #1

    s-f

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    Problem: (a) What is the capacitance of the 2 conductors +20nC and -20nC? (b) If the voltage difference between the 2 conductors increase to 250 V, then what else changes?

    a). I calculated that ΔV = 100 V. So then I plugged into the formula C = Q/ΔV. I thought 20 nC = 2 x 10^-8 C, which divided by 100 V = 2 x 10^-9C but the answer is 2 x 10^-10 C. What am I doing wrong? I know this is very simple but I have never studied physics before and am terrible at math.

    b). charge of the conductors increases to keep capacitance constant, since capacitance is a property of area and distance between plates (I think this is right but please tell me if it's wrong!)

    Thanks in advance!
     
  2. jcsd
  3. Jul 25, 2012 #2

    berkeman

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    Staff: Mentor

    Welcome to the PF.

    Where did the 100V come from? Is it given for part a)?
     
  4. Jul 25, 2012 #3

    s-f

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    Thanks. Actually the problem had more steps before this and Ohm's Law was used to calculate Voltage = 100 V (I have the answers so I know it's correct). The part I'm unsure of is how C = 2 x 10^-10 Farads (not Coulombs - I accidentally wrote C instead of F earlier!).
     
  5. Jul 30, 2012 #4

    s-f

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    Anyone? I would really appreciate it : )
     
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