Calculate CM Speed of Rod on Compressed Spring

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SUMMARY

The discussion focuses on calculating the speed of the center of mass (CM) of a thin uniform rod with mass M = 0.31 kg and length L = 0.45 m, pivoted at one end and released from an angle θ1 = 57°. The rod moves through a horizontal position and stops at an angle θ2 = 107°. The solution requires applying principles of rotational dynamics and energy conservation to find the CM speed at the horizontal position (B). The absence of a visual figure is noted as a barrier to understanding the problem fully.

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Homework Statement



A thin uniform rod has mass M = 0.31 kg and length L= 0.45 m. It has a pivot at one end and is at rest on a compressed spring as shown in (A). The rod is released from an angle θ1= 57o, and moves through its horizontal position at (B) and up to (C) where it stops with θ2 = 107o, and then falls back down. Friction at the pivot is negligible. Calculate the speed of the CM at (B).

http://schubert.tmcc.edu/res/msu/physicslib/msuphysicslib/21_Rot3_AngMom_Roll/graphics/prob32a_RodOnSpring.gif

Homework Equations





The Attempt at a Solution



Not sure where to start on this one. Thank you for your time and any help provided.
 
Last edited by a moderator:
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Where is the figure? Problem is not clear without that.
 

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