Hi everyone, Say I have a series DC circuit. The circuit contains a 100V DC source, a switch, a 1.5H inductor, and a 1nF capacitor (all in series). If I close the switch for 2uS what is the current at that time? Initially I thought I could rearrange V=L*di/dt to V*Ton/L = di/dt which would be 100*.000002/.150=1.3mA??? For some reason I am thinking this is not right since the capacitor charge should also effect the current. Can anyone help me understand and calculate this correctly?