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Say I have a series DC circuit. The circuit contains a 100V DC source, a switch, a 1.5H inductor, and a 1nF capacitor (all in series).

If I close the switch for 2uS what is the current at that time?

Initially I thought I could rearrange V=L*di/dt to

V*Ton/L = di/dt which would be 100*.000002/.150=1.3mA???

For some reason I am thinking this is not right since the capacitor charge should also effect the current.

Can anyone help me understand and calculate this correctly?