Calculate Electric Potential Change: +1 & -3 Micro-Coulombs

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SUMMARY

The discussion focuses on calculating the change in electric potential (Voltage) when moving a -3 micro-coulomb charge from 2 meters to 4 meters away from a +1 micro-coulomb charge. The primary equation referenced is ΔV = -∫E(x)dx, with integration limits from 2 to 4 meters. Participants clarify that the negative charge does not directly factor into the integral for electric potential change, emphasizing that electric potential is inversely proportional to distance (r) from the charge.

PREREQUISITES
  • Understanding of electric potential and its relationship with charge
  • Familiarity with Coulomb's Law
  • Basic calculus for evaluating integrals
  • Knowledge of electric field concepts
NEXT STEPS
  • Study the derivation of electric potential from electric field concepts
  • Learn about the superposition principle in electrostatics
  • Explore the implications of charge movement on electric potential
  • Investigate the relationship between electric potential and electric field strength
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Students in physics, particularly those studying electromagnetism, as well as educators and anyone seeking to deepen their understanding of electric potential and charge interactions.

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Homework Statement



There is a +1 micro-coulomb charge at the origin and a -3 micro-coulomb charge at 2 meters away along the x-axis. I am suppose to find the change in Voltage if second charge is moved to 4 meters away from the origin.

Homework Equations



I am thinking of using delta V= - integral of E(x)dx , where the limits of integration is from 2 to 4.

The Attempt at a Solution



i am not sure why the negative three micro-coulomb isn't included when using this equation. can someone explain why?
 
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Well I'll tell you're over complicating it. Pretty much the only equation you need is electric potential = somestuff / r

You don't even need to know what the somestuff is, only that potential is inversely proportional to r
 

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