Two charges and electric field?

Ginepri
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Homework Statement


Two charges are placed on the x axis. One charge (q1= +8.5 micro coulombs) is at x1 = +3.0cm and the other (q2 = -21 micro coulombs) is at x1 = +9.0cm. Find the net electric field (magnitude and direction) at (a) x = 0cm and (b) x = +6.0cm

Homework Equations


E = kq1/r^2

The Attempt at a Solution


(9x10^9 Nm^2/c^2)(8.5x10^-6 c) / (0.03m)^2 + (9x10^9 Nm^2/c^2)((-21)x10^-6 c) / (0.09m)^2 =

8.5x10^7 N/c + -2.3x10^7 N/c =

6.2x10^7 N/c

Answer key says -6.2x10^7 N/c, I can't figure out why the electric field is negative.
 
on Phys.org
Ginepri said:

Homework Statement


Two charges are placed on the x axis. One charge (q1= +8.5 micro coulombs) is at x1 = +3.0cm and the other (q2 = -21 micro coulombs) is at x1 = +9.0cm. Find the net electric field (magnitude and direction) at (a) x = 0cm and (b) x = +6.0cm

Homework Equations


E = kq1/r^2

The Attempt at a Solution


(9x10^9 Nm^2/c^2)(8.5x10^-6 c) / (0.03m)^2 + (9x10^9 Nm^2/c^2)((-21)x10^-6 c) / (0.09m)^2 =

8.5x10^7 N/c + -2.3x10^7 N/c =

6.2x10^7 N/c

Answer key says -6.2x10^7 N/c, I can't figure out why the electric field is negative.
Please state coulomb's Law as it was given to you in class, or in your textbook?
 

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