Calculate Electron Flow in 3 Secs

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mp252
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i was stuck on this equation if a current of 2 A flows through a lamp when it is connected by copper wire of cross-sectional area 1 mm2 to the terminals of a battery. how many electrons will leave the negative terminal of the battery in 3 seconds? (obiviously the charge of electrons is e=1.602*10–19 C.
 
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mp252 said:
1a=1c/1s
Right. An Ampere is one Coulomb of charge per second. How many electrons make up one Coulomb?