Calculate Electron Flow in 3 Secs

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To calculate the number of electrons leaving the battery's negative terminal in 3 seconds with a current of 2 A, first recognize that 1 Ampere equals 1 Coulomb per second. Therefore, in 3 seconds, the total charge is 2 A x 3 s = 6 Coulombs. Given that the charge of a single electron is approximately 1.602 x 10^-19 C, the number of electrons can be calculated by dividing the total charge by the charge of one electron. This results in approximately 3.75 x 10^19 electrons leaving the battery in that time frame. Understanding these principles is crucial for accurately calculating electron flow in electrical circuits.
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i was stuck on this equation if a current of 2 A flows through a lamp when it is connected by copper wire of cross-sectional area 1 mm2 to the terminals of a battery. how many electrons will leave the negative terminal of the battery in 3 seconds? (obiviously the charge of electrons is e=1.602*10–19 C.
 
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What is the definition of an ampere in terms of coulombs and seconds?
 
1a=1c/1s
 
mp252 said:
1a=1c/1s
Right. An Ampere is one Coulomb of charge per second. How many electrons make up one Coulomb?
 
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