Calculate EMF: 3.25 ohm, 440 mH, 3.00 A, 3.60 A/s

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SUMMARY

The discussion focuses on calculating the electromotive force (emf) across a coil with a resistance of 3.25 ohms and an inductance of 440 mH, given a current of 3.00 A that is increasing at a rate of 3.60 A/s. The relevant formula used is emf = -L (dI/dt), where L is the inductance and dI/dt is the rate of change of current. By substituting the values into the equation, the emf can be determined, providing insights into the behavior of the coil under these conditions.

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  • Understanding of electromagnetic induction principles
  • Familiarity with the formula emf = -L dI/dt
  • Basic knowledge of electrical resistance and inductance
  • Ability to perform calculations involving ohms and henries
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Shackleford
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A coil has a 3.25 ohm resistance and 440 mH inductance. If the current is 3.00 A and is increasing at a rate of 3.60 A/s, what is the potential decrease across the coil at this moment?

The only equation I know to use is

emf = - L dI/dt
 
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Hi Shackleford,

Shackleford said:
A coil has a 3.25 ohm resistance and 440 mH inductance. If the current is 3.00 A and is increasing at a rate of 3.60 A/s, what is the potential decrease across the coil at this moment?

The only equation I know to use is

emf = - L dI/dt

What would be the emf across a 3.25 ohm resistor in this situation?
 
alphysicist said:
Hi Shackleford,



What would be the emf across a 3.25 ohm resistor in this situation?

Hello. Sorry. I took another quick stab at this problem and solved it correctly. I've kind of had a cold/mild flu lately.
 

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