Calculate Energy Needed to Heat 4.6 kg Water

[runicle]

Determine the energy needed to raise the temperature of 4.6 of 0 degrees celsius ice to 106 degrees celsius vapour given the values for water: 5 marks
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l[subscript]f= 333kJ/kg, l[subscript]v = 2255 kJ, c[subscript]liquid = 4200 J/kg c[subscript]vapour = 2000 J/Kg degrees celsius

I just have one question, do you need all these equations?:
Q = mc[delta]t, Q = ml[subscript]f Q=ml[subscript]v
and basically add them all up?

 

[andrewchang]

yup, that's right

 

[civil_dude]

I can tell you that it is a four part question.

A) Energy to melt the solid ice.
B) Energy to raise liquid to 100.
C) Energy to evaporate into vapor.
D) Energy to raise vapor to 106.