Calculate Heat of Formation for SO3 Gas using Hess' Law - Step by Step Guide"

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SUMMARY

The heat of formation for one mole of SO3 gas is calculated using Hess' Law, based on the provided reactions. The first reaction, S8(s) + 8O2(g) → 8SO2(g) releases 2378.4 kJ, while the second reaction, SO2(g) + 1/2O2(g) → SO3(g) releases 99.0 kJ. By manipulating these equations, the overall reaction S8(s) + 12O2(g) → 8SO3(g) is derived. The total heat of formation is determined to be -396.3 kJ per mole of SO3.

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GodsChild086
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Compute the heat for formation of one mole of SO3 gas from the following data:

Sorry I don't know how to do subscripts...

S8(s) + 8O2(g) --> 8SO2(g) + 2378.4 kJ
SO2(g) + 1/2O2(g) --> SO3(g) + 99.0 kJ

I don't have a clue where to start...
 
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Since you are finding out the heat for formation of one mole of SO3 gas, it is necessary for you to find out the reaction equation for the foramation of SO3 gas using the given data first. By addition/subtraction/multiplication/division the given data, you can find out the equation, and therefore find out the heat for formation.
 
So is this right?

I'm going to multiply the second equation by 8...

S8(s) + 8O2(g) --> 8SO2(g) + 2378.4 kJ
8SO2(g) + 4O2(g) --> 8SO3(g) + 792 kJ

Balanced equation (well adding the both of them together):

S8(s) + 12O2(g) --> 8SO3(g)

________________________________________________________________
-2378.4 kJ + (-792 kJ) = -3170.4 kJ

-3170.4 kJ/8 mol x 1 mol = -396. 3 kJ[/color] (the mol's will cancel)
 
Um, Yes. I think it is right!
 

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