Calculate Height of Object & Bob at Top of Pendulum Swing

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To calculate the height of an object and the pendulum bob at the top of its swing, the length of the pendulum (L) and the angle (theta) are essential. The problem involves breaking down the scenario into two triangles: an isosceles triangle and a right triangle. The height (h) can be derived using the formula h = L - Lcos(theta), which relates the height to the pendulum length and the angle of displacement. This approach utilizes trigonometric functions to solve for the height needed for further mechanical energy calculations. The discussion emphasizes the importance of geometry in solving physics problems.
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Homework Statement



What is the height of the object and pendulum bob at the top of the swing, when they have reached their maximum displacement? Keep in mind that the pendulum has a length L and swings through an angle theta.

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Homework Equations



Trigonometric functions


The Attempt at a Solution


I am trying to find the height, h in order to be able to complete a mechanical energy problem that I am fully able to complete. My problem is that my geometry might be a little rusty and I can't seem to solve for this needed value.

I broke down the diagram into two triangles-- one is isosceles with two sides equal to L which converge to form angle theta.

The other triangle (a right triangle) shares the side opposite theta and has a leg equal to h.


Now, there must be some fancy geometry trick to be able to solve for h in terms of L and theta, but I honestly can't seem to figure it out. I am sure there is a rule for triangles that I am forgetting that will solve this.
 
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Draw a line from where the pendulum is up at the angle... draw a line from there perpendicular to the vertical (the line along which the pendulum was initially hanging)

use the right triangle formed by the angle theta... the line from the pivot to where the pendulum is up at theta (this is the hypoteneuse with length L)... and the line that you just drew (opposite to theta)...

what is the length of the side adjacent to theta. use this to get h.
 
h = L-Lcos(theta)

Thanks!
 
vertabatt said:
h = L-Lcos(theta)

Thanks!

no prob.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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