Calculate Linear Velocity: 180 deg/s & 0.5 m

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Homework Help Overview

The problem involves calculating the linear velocity of a foot based on a given angular velocity of a dynamometer and the distance from the knee joint to the foot. The subject area pertains to rotational motion and its relationship to linear motion.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the formula for linear velocity, questioning the correctness of unit conversions and the handling of angular measurements. There is an exploration of the implications of using degrees versus radians in calculations.

Discussion Status

Some participants have provided guidance on unit conversions and the correct application of the formula. There is acknowledgment of potential confusion regarding units, but no explicit consensus has been reached on the final answer.

Contextual Notes

The original poster is required to provide a numerical answer without units, which may influence how participants approach the problem and discuss the calculations.

PepperABLF12
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Homework Statement



What is the linear velocity of the foot if the angular velocity of the dynamometer was 180 degrees/s and the distance from the knee joint to the foot is 0.5 m. Give your answer rounded to two decimal places in m.s-1. (Do not include units in answer).

Homework Equations



linear velocity = angular velocity (w) x radius (r).
linear velocity = w x r.

The Attempt at a Solution



w = 180 degree/s
r = 0.5m
linear velocity = ?

linear velocity = w x r
linear velocity = 180 x 0.5
linear velocity = 90 degrees/s

To find radians, 90/57.3 = 1.57 m/s

Is this correct? And in the right units?

Please help and thank you! :)
 
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Well, your relevant equation gives ##0.5 {\rm m}\, \times \,\pi \, {\rm rad/s} = 1.57 \,{\rm m/s}## straightforward.

But your dealing with units is a bit messy. Especially the 90 degrees/s is objectionable. A linear velocity has dimension length/time. The numerics are fine, but the dimensions should read something like: degrees/s / radians/degree x meters/radian

THe writer of the exercise doesn't want to be bothered by these considerations, so he/she asks for a number only.

In my first sentence I let the radians disappear, you could say that I cheat too. My defence is: radians is arc per radius, so length/length and thereby dimensionless: it can be skipped in dimensional expressions.
 
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Thank you so much! Great help :)
 
It is easier to understand if you convert to radians first and then calculate the linear velocity.
 
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