Calculate Mass of Missing Piece Exploding Boulder

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SUMMARY

The discussion focuses on calculating the mass of a missing piece from an exploding boulder, which was initially stationary. The momenta of three pieces are provided: piece A (1kg at 10m/s West), piece B (2kg at 20m/s North), and piece C (4kg at 10m/s East). Using the principle of conservation of momentum, the total momentum before and after the explosion must equal zero. The calculated mass of the missing piece, based on the provided velocity magnitude of 25m/s, results in an invalid negative mass, indicating a need to consider vector components for accurate momentum calculations.

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yoleven
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Homework Statement


A stick of dynamite blows a boulder into 4 pieces. The boulder was stationary before the explosion. After the explosion, three of the pieces have the following momenta;
piece a = 10m/s West 1kg
piece b = 20m/s North 2kg
piece c = 10m/s East 4kg
Calculate the mass of the missing piece if the magnitude of its velocity is 25m/s



Homework Equations


Ptotal(initial)=Ptotal(final)
P=mv


The Attempt at a Solution


Since the boulder was not moving, its momentum is zero. The momentum of each piece is its mass x its velocity. Each piece's momentum added to each other will equal zero because momentum is conserved. So I get;
0=m1v1+m2v2+m3v3+m4v4
0=1kg(10m/s W)+2kg(20m/s N)+4kg(10m/s E)+m4(25m/s)
-90kgm/s=m4(25m/s)
m4=-3.6kg
Now I can't have a negative mass, so what can I do to solve this?
 
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The momentum is a vector you can't just add all the components like that. It's a 2-dimensional situation.
And you have given the magnitude of it's velocity, ie it's speed. So you also to need to figure out in what direction the 4th piece goes, but you don't need to calculate it though, only that it will be in your equations.
 
Thank you.
 

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