Calculate Minimum Volume for Balloon Lift Off w/ Helium & Load

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SUMMARY

The minimum volume required for a helium-filled balloon to lift off with a total load of 320 kg (80 kg for the balloon and 240 kg for the load) is determined by applying Archimedes' principle. The density of helium is 0.178 kg/m³, while the density of the surrounding air is 1.29 kg/m³. The balloon will float when the weight of the displaced air equals the total weight of the balloon and its load. Thus, the volume of helium must equal the volume of air displaced, leading to the equation: V = (mass of balloon + load) / density of air.

PREREQUISITES
  • Understanding of Archimedes' principle
  • Basic knowledge of density calculations
  • Familiarity with mass and volume relationships
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Calculate the minimum volume of helium required using the formula V = (mass of balloon + load) / density of air.
  • Explore the implications of varying the density of helium and air on lift-off volume.
  • Investigate the effects of balloon material on overall weight and lift capacity.
  • Learn about real-world applications of buoyancy in various engineering fields.
USEFUL FOR

Students studying physics, engineers working on buoyancy-related projects, and anyone interested in the principles of lift and gas densities.

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Homework Statement


A balloon is to be filled with helium(density = 0.178kg/m^3) while the air outside has density of 1.29km/m^3. The mass of the empty balloon is 80.0kg and it is to lift a load of 240kg. What minimum volume is necessary for the lift off? Assume that the balloon material and the load occupy negligible volumes.


Homework Equations



density = M/V

The Attempt at a Solution



I'm not quite sure how to start with this question. Can someone help me please?
 
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The balloon will float when the weight of the displaced air is equal to the weight of the balloon with load.

Volume of the balloon = mass of the balloon/density of helium.
 
hmmm. not quite getting it.

This is archemides' principle right? so wouldn't the equation be:

density of balloon/ density of gas = volume of gas/ volume balloon??
 
Mass of the displaced air = Ma = (240 + 80 + VHe* ρHe) kg.

volume of the air = Ma/ρa = ... = Volume of the balloon.

So Vb*ρa = (240 + 80 + VHe* ρHe) kg

Ηere volume of the balloon is equal to the volume of He.
 
k...just want to clarify. The balloon will float when the mass of the displaced air is equal to the weight of the balloon plus the load.

therefore,
Ma = (240 + 80)kg including helium??

how come is volume of air = volume of balloon?

sorry...a bit confused. I'm not great with this kind of physics.
 
mizzy said:
k...just want to clarify. The balloon will float when the mass of the displaced air is equal to the weight of the balloon plus the load.

therefore,
Ma = (240 + 80)kg including helium??

how come is volume of air = volume of balloon?

sorry...a bit confused. I'm not great with this kind of physics.

(240 + 80)Kg is mass without helium. Mass of the displaced air is equal to the (mass of helium + 240 + 80) kg. Balloon will float only when it is filled with the helium. Since the balloon material and the load occupy negligible volumes, volume of the helium = volume of the air.
 

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