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## Homework Statement

In a cubical volume, 1.05 m on a side, the electric field is given by the formula below, where

*E*= 1.25 N/C and

_{0}*a*= 1.05 m.

*E*(1 +

_{0}*z*/

*a*) i +

*E*(

_{0}*z*/

*a*) j

The cube has its sides parallel to the coordinate axes, see the figure. Determine the net charge within the cube.

## Homework Equations

φ

_{e}= ∫E⋅dA = q

_{enc}/ε

_{0}

## The Attempt at a Solution

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So I know that I need to calculate the net flux through all the 6 faces of the cube in order to solve for q

_{enc}. I know that φ

_{+z}and φ

_{-z}are equal to 0.

I think I am doing something wrong because it seems like they would cancel out?

φ

_{+x}= E

_{0}a

^{2}∫ (1+z/a) dz

φ

_{-x}= -E

_{0}a

^{2 }∫ (1+z/a) dz

φ

_{+y}= E

_{0}a

^{2 }∫ (z/a) dz

φ

_{-y}= -E

_{0}a

^{2 }∫ (z/a) dz

Also, I would evaluate the integrals from 0 to a right?

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