Calculate Orbital Angular Momentum

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SUMMARY

The discussion focuses on calculating the orbital angular momentum of a satellite with mass m moving in a circular orbit of radius r around a larger mass M. The formula derived for the orbital angular momentum is l = m \sqrt{GMr}, assuming that mass M is significantly larger than mass m. The velocity of the satellite is given by v = √(GM/r), which is critical for determining the angular momentum. The center of mass calculations and the relationship between the masses are also discussed to clarify the derivation.

PREREQUISITES
  • Understanding of classical mechanics and angular momentum
  • Familiarity with gravitational concepts, specifically Newton's law of gravitation
  • Knowledge of center of mass calculations
  • Basic proficiency in algebra and square root functions
NEXT STEPS
  • Study the derivation of angular momentum in different gravitational contexts
  • Explore the implications of mass ratios in orbital mechanics
  • Learn about the conservation of angular momentum in closed systems
  • Investigate the effects of varying mass distributions on orbital dynamics
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Students and professionals in physics, particularly those focusing on mechanics and astrophysics, as well as anyone interested in understanding orbital dynamics and angular momentum calculations.

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Satellite of mass m is moving with velocity v in a circular orbit of radius r about mass M.

Find the orbital angular momentum.

Know

v = \sqrt{\frac{GM}{r}}

Orbital angular momentum of a system is defined as the angular momentum of the center of mass of the system.

Let the origin be at mass M.

r_{cm} = \frac{m}{M + m} r
v_{cm} = \frac{v}{r} \frac{m}{M + m} r = \frac{vm}{M+m}

l = r_{cm} \times p_{cm} = (M + m) r_{cm} v_{cm} = \frac{m^2 rv}{M+m} = \frac{m^2}{m+M} \sqrt{GMr}

Correct answer in text is m \sqrt{GMr}
 
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I think it is being assumed that M is MUCH bigger than m.
 
Ok thanks, just wanted to be sure.
 

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