Calculate Phosphorus Atoms in 8.75 Moles of H2P2O7 | Stoichiometry Help

[sweetshelly]

This is the question:
How many phosphorus atoms are contained in 8.75 moles of H2P2O7? Put your answer in E-format with 1 number before and 2 numbers after the decimal place. e.g., 6.02 x 1023 would be input as 6.02E23.



the answer is : 1.05E25 (1.05 × 1025)

I really have no idea where to start. Please someone help me

 

[siddharth]

To start off, how many atoms are there in 1 mole of phosphorus atoms?

This link should aid your understanding.
http://www.fordhamprep.org/gcurran/sho/sho/skills/moleconex.htm

 

[kinthos]

You've been given 8.75 moles of H2P2O7, which contains 2x8.75 moles of H, 2x8.75 moles of P, and 7x8.75 moles of O. In one mole of anything (H2P2O7, P atoms, eggplants, etc), there are 6.02E23 particles.

 

[sweetshelly]

You've been given 8.75 moles of H2P2O7, which contains 2x8.75 moles of H, 2x8.75 moles of P, and 7x8.75 moles of O. In one mole of anything (H2P2O7, P atoms, eggplants, etc), there are 6.02E23 particles.

wow thank you so much. This explanation gave me the correct answer. I really appreciate your help a lot. This is part of our exam review. If I didn't know how to solve this problem I would miss it. I can't afford not knowing something b/c we only have 20 questions total. I need an A on tomorrow test to make an A average for the semester. You're the greatest