Calculate power consumed by pressure drop

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Discussion Overview

The discussion revolves around calculating the power consumed by a HVAC VAV box due to a pressure drop, specifically focusing on the energy utilization of air moving through a restriction. Participants explore the relevant equations and factors affecting the calculation, including assumptions about fluid properties and efficiencies.

Discussion Character

  • Technical explanation, Mathematical reasoning, Debate/contested

Main Points Raised

  • One participant seeks assistance in deriving an equation for energy consumption of air at specific conditions, mentioning the use of uncompressible fluid and ideal gas assumptions.
  • Another participant suggests that the calculation should focus on watt-hours rather than watts, providing a preliminary calculation based on pressure drop and air flow rate.
  • A subsequent reply agrees with the initial calculations and expresses a nostalgic sentiment about engaging with such problems.
  • Another participant introduces a formula using English units and provides a different energy estimate, noting that fan efficiency is not included in their calculation.
  • Concerns are raised about the efficiency of the fan and motor, with one participant suggesting that motor efficiency could be around a couple of percent, while another mentions that larger motors can achieve efficiencies upwards of 95% and discusses the efficiency of variable frequency drives (VFDs) and pulley-drives.

Areas of Agreement / Disagreement

Participants generally agree on the need to consider fan and motor efficiencies in the calculations, but there are differing views on the specific values and methods to use for these efficiencies, as well as the initial calculations presented.

Contextual Notes

Participants have not resolved the assumptions regarding fluid properties, the impact of fan and motor efficiencies, and the specific formulas to use for the calculations. There is also a lack of consensus on the correct approach to convert between units.

Who May Find This Useful

Individuals interested in HVAC systems, energy consumption calculations, and fluid dynamics may find this discussion relevant.

NotionCommotion
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Hello all! I am interested in how much energy a HVAC VAV box consumes. Can anyone help me come up with the following equation? I don't need to know the exact formula, and can assume an uncompressible fluid and/or ideal gas. Been about 20 years since I have done this and am a bit rusty. Thank you

How many watts are utilized by 1,000 CFM of 55 F air at 2" water pressure above atmosphere going through a restriction that results in a static pressure drop of 0.2" wp over a duration of 1 year?
 
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Actually, looks like not watts but watt hours, right?

Do I have this correct?

p=0.2" wc = 50 Pa = 50 n/m^2
Q=1,000 CFM = 0.5 m^3/s
P=p x Q = 25 n-m/s = 25 j/s
For 365 days, E = 788x10^6 j = 220 kw-h

Thanks
 
Last edited:
That looks reasonable to me.
 
Thanks

PS. I miss doing this stuff!
 
Starting in English units, it is:
Dp*CFM/6356=hp

Conversion: 746 watts/hp.

I get 206 kWh. Note also, this doesn't include fan efficiency. For a well operating commercial fan, assume 65%. That puts you up to 317 kWh.
 
Good point about fan efficiency. What about the motor efficiency? A couple percent?
 
NotionCommotion said:
Good point about fan efficiency. What about the motor efficiency? A couple percent?
Larger motors running near full speed get upwards of 95%. A VFD is about 98% efficient. The pulley-drive on a fan, 90-95% efficient.
 

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