- #1
Hugh99
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I'm trying to build a tank to hold diesel fuel, it will be on skids to lift with a fork lift but I also want to extend the the sides to provide a way to raise the tank from two attachment points on each side. The sides will be 1/4 A36 steel plate and the rest of the tank will be 10 gauge (0.140625). The tank should weigh around 350 lbs and hold 119 gallons of diesel. Using maximums that's 119x7.5 lbs = 892.5 lbs, including the weight of the tank that is roughly 1250 lbs.
Assuming the holes at the tope of the side plate are 2 in diameter and the shear formula F = P x T X PSI
I was going to calculate P as 2 in x pi and then divide by the portion of the whole that would be in contact with the rigging, so assuming 1/4 of the perimeter is in contact with perimeter, = 1.57
F = 1.57 x .25 x 36,000
F = 14,130 lbs per hole, so I should be able to support over 28,000 pounds for the two holes.
Does my math look correct?
If I left the sides as 10 gauge, it looks like it could still support 7900 lbs per hole for total of 15,800 lbs so I may not need 1/4 plate on the sides.
Thanks
Assuming the holes at the tope of the side plate are 2 in diameter and the shear formula F = P x T X PSI
I was going to calculate P as 2 in x pi and then divide by the portion of the whole that would be in contact with the rigging, so assuming 1/4 of the perimeter is in contact with perimeter, = 1.57
F = 1.57 x .25 x 36,000
F = 14,130 lbs per hole, so I should be able to support over 28,000 pounds for the two holes.
Does my math look correct?
If I left the sides as 10 gauge, it looks like it could still support 7900 lbs per hole for total of 15,800 lbs so I may not need 1/4 plate on the sides.
Thanks