Calculate sin75 without calculator

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SUMMARY

The discussion focuses on calculating sin(75°) without a calculator by utilizing trigonometric identities and angle addition formulas. The user initially attempted to derive sin(75°) using a triangle with angles 15°, 75°, and 90°, but encountered issues when applying the Pythagorean theorem. A more effective method was suggested, breaking down sin(75°) into sin(45° + 30°) and applying the sine addition formula, resulting in the expression ¼(√6 + √2). This method provides a clear and correct calculation of sin(75°).

PREREQUISITES
  • Understanding of trigonometric functions, specifically sine and cosine.
  • Familiarity with the sine addition formula: sin(α + β) = sin(α)cos(β) + cos(α)sin(β).
  • Knowledge of basic triangle properties and the Pythagorean theorem.
  • Ability to manipulate square roots and fractions in mathematical expressions.
NEXT STEPS
  • Study the sine addition formula in detail to understand its applications.
  • Learn about the double angle and half angle formulas for sine and cosine.
  • Practice calculating sine and cosine for various angles using trigonometric identities.
  • Explore closed-form formulas for sine and cosine of angles from 1° to 89°.
USEFUL FOR

Students studying trigonometry, educators teaching angle calculations, and anyone looking to enhance their understanding of trigonometric identities and angle manipulation.

Robin04
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Homework Statement


Calculate sin75 without calculator![/B]

Homework Equations

The Attempt at a Solution


I constructed a triangle with angles 15, 75 and 90 then I defined sin75 by the sides. In a previous exercise the task was the same but with tg15 and I used the result in this execise too.
I wrote the equation: tg15 = b/a and if I express b and put it in the Pythagorean theorem I get the right result. However, if I express a and put it in the Pythagorean theorem I got a wrong result and I don't know why is this happening. I looked through it and I haven't find any calculation error... The second way is a lot longer but I should work. :(

http://kepfeltoltes.hu/thumb/150902/IMG_0122_www.kepfeltoltes.hu_.jpghttp://kepfeltoltes.hu/thumb/150902/IMG_0123_www.kepfeltoltes.hu_.jpg
 
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Are you familiar with double angle and half angle formulas? How is sin75 related to cos15? What is cos(2θ) in terms of cosθ?

Chet
 
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Robin04 said:
I know that this is not a physics homework, but I didn't find any subforum for my trigonometry math homework.

1. Homework Statement
Calculate sin75 without calculator!

Homework Equations

The Attempt at a Solution


I constructed a triangle with angles 15, 75 and 90 then I defined sin75 by the sides. In a previous exercise the task was the same but with tg15 and I used the result in this execise too.
I wrote the equation: tg15 = b/a and if I express b and put it in the Pythagorean theorem I get the right result. However, if I express a and put it in the Pythagorean theorem I got a wrong result and I don't know why is this happening. I looked through it and I haven't find any calculation error... The second way is a lot longer but I should work. :(

http://kepfeltoltes.hu/thumb/150902/IMG_0122_www.kepfeltoltes.hu_.jpghttp://kepfeltoltes.hu/thumb/150902/IMG_0123_www.kepfeltoltes.hu_.jpg

You really should type out your work; most helpers here (me included) will ignore any of the details in your post.

I am willing to offer a hint, though: if you look on-line you can find documents that give closed-form formulas for sines or cosines of all angles from 1 degree to 89 degrees in increments of 1 degree.
 
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Chestermiller said:
Are you familiar with double angle and half angle formulas? How is sin75 related to cos15? What is cos(2θ) in terms of cosθ?

Chet
I haven't learned them but I have the formulas in my book.
 
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Break the angle 75 into component angles which are more familiar e.g 15,30 ,45 , then apply sin(alpha+beta) formula...
sin 75
= sin(45 + 30)
= sin45cos30 + cos45sin30
= (½√2)(½√3) + (½√2)(½)
= ¼(√6 + √2)
 
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Hamza Abbasi said:
Break the angle 75 into component angles which are more familiar e.g 15,30 ,45 , then apply sin(alpha+beta) formula...
sin 75
= sin(45 + 30)
= sin45cos30 + cos45sin30
= (½√2)(½√3) + (½√2)(½)
= ¼(√6 + √2)

PF helpers are not allowed to give complete solutions!
 
Ray Vickson said:
PF helpers are not allowed to give complete solutions!
Oh ! Sorry I didn't knew that , I will try to avoid it in the future.
 
Thanks for your answer! :) But can you help me with explaining why my solution doesn't work? They seem completely equivalent for me.
 

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