Calculate speed in a copper wire

Click For Summary

Discussion Overview

The discussion revolves around calculating the speed of data transmission in a copper wire, specifically focusing on the impact of various parameters such as channel bandwidth, signal-to-noise ratio (SNR), and the effects of distance on signal quality. Participants explore theoretical calculations and seek clarification on how to graph the relationship between speed and range.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents an initial calculation of channel capacity using the formula C=B log2(1+S/N) and proposes a speed of 7.2 Mbit/s based on a bandwidth of 900 MHz and an SNR of 30 dB.
  • Another participant questions the calculation of 7.2 Mbit/s, noting that they arrive at the same number by multiplying the capacity of a single channel by the number of channels.
  • A later reply corrects the bandwidth value from 900M to 900k, leading to a revised capacity of 8.97 Mbit/s.
  • One participant expresses uncertainty about the original question, suggesting that the task may involve determining the distance at which the SNR falls below 30 dB and how this relates to the signal at the source.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the calculations, with some expressing confusion about the parameters involved and the implications of distance on SNR. Multiple interpretations of the task remain evident.

Contextual Notes

There are unresolved issues regarding the assumptions made about bandwidth, SNR, and the relationship between speed and distance. The calculations depend on specific definitions and conditions that have not been fully clarified.

dont_know
Messages
3
Reaction score
0
Okey, I have a problem now. I´m suposed to sketch a graf of how long range on a copper wire some different speeds have ex 256 kbit/s etc.

I have 225 channels of each 4kHz and it can transfer 4000 symbols/sec. The effect on each channel is 0.1mW and the noise is -100dBm.

The signal is reduced by 18 db/km

I´m using QAM-256 that means i can transfer 8 bits/symbol. It demands a SNR of 30db. Now i´m going to sketch a graf of the distance of some different speeds.


This far have I come (or am I totally lost?):

The bandwith is 900Mhz and SNR of the channel is 30db (30db = 10 log 1000 = S/N=1000) that gives: C=B log2 (1+S/N) C=900M*log2(1+1000)=7.2 Mbit/s

or a single channel:

C=4000*log2(1+1000)=398.7 kbit/s and then we have 225 channels that makes: 225*398.7=89,7 Mbit/s

Which one is the correct? If one is that say... That is speed att approximate 1 m and then I have to calculate the range of the speed with the 18 db/km?

But what about the symbols and bits? The effect of the channels and the noise?

Feeling quite lost now. Would be grateful for some help!

//Dont_know
 
Physics news on Phys.org
C=900M*log2(1+1000)=7.2 Mbit/s

how are you getting 7.2Mbit/s here? I'm getting the same number you got using single channels and multiplying by 225.
 
Oh. That is correct. When I checked what I wrote. I see some mistakes from my side. It shouldn´t be 900M but 900k.

I have looked at it on many different angles now. I´m staring to get somewhere now. But the limit in this channel is 8.97 Mbit/s. With the right equation:

C=900k*log2(1+1000)=8.97 Mbit/s
 
Not sure if I'm fully understanding the question... it's been years since I did this stuff... But are you supposed to pick rates in bits/s and then plot the range for them... ie the distance when the signal to noise ratio becomes less than 30dB?

So what is the signal to noise ratio at the source... and how does it change with distance... is that what you need to work out?

just thinking out loud...
 

Similar threads

Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
28K
Replies
1
Views
8K
Replies
1
Views
6K
Replies
5
Views
6K