Calculate the barbell acceleration while being lifted

[doggydan42]

Clockwise=(850x0)+(100x0.7)+(750x1.2)=850+70+900=1820Nm

anticlockwise= fx1.4= 1820/1.4=1300N?

$f*1.4 \neq 1820/1.4$

Make each step clear, and keep track of units.

 

[doggydan42]

True, f=3250/3 f=1083N

Where are you getting 3250? Your had the right idea last time. Just make it clear and write down units at each step.

 

[doggydan42]

The answer is 1300N, am I not right?

That's not right. Show your work clearly.

 

[Jeff97]

(850x0)+(100x0.7)+(750x1.2)=970Nm

Fb x 1.4 970/1.4= 692NIS this correct?

 

[doggydan42]

Fb x 1.4 970/1.4= 692N

Check your rounding.

 

[Jeff97]

693N

 

[doggydan42]

693N

That looks right to me.

 

[Jeff97]

Thanks for your time. Last thing the ground support force, force is just 850N isn't it.

 

[doggydan42]

Thanks for your time. Last thing the ground support force, force is just 850N isn't it.

I believe so.