Calculate the center of mass of a semi-circular metal plate

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SUMMARY

The discussion focuses on calculating the center of mass of a semi-circular metal plate with uniform density ρ and thickness t, where the radius is denoted as a. The mass of the plate is established as 1/2 (ρπat²). The equations for the center of mass are defined as xcm = 1/M ∫[xdm] and ycm = 1/M ∫[ydm]. The user attempts to derive the center of mass but initially miscalculates the height of the rectangle, leading to an incorrect result of 2a/π.

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  • Understanding of center of mass calculations
  • Familiarity with calculus, specifically integration
  • Knowledge of uniform density and its implications
  • Basic geometry of semi-circles
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Homework Statement



(Q) Calculate the center of mass of a semi-circular metal plate of uniform density ρ and thickness t. Let the radius of the plate be a. The mass of the plate is thus 1/2 (ρπat2). In your co-ordinate system, you must consider the x-axis passing through the bottom of the plate and the y-axis to be bisecting the metal plate.


Homework Equations



xcm = 1/M int [xdm] and ycm = 1/M int[ydm]

The Attempt at a Solution



If we take a small change in length dx, the area of the rectangle formed will be adx. The volume therefore will be atdx. The change in mass dm = ρatdx.

Substituting and integrating gives us 2a/π which is definitely wrong since under the is co-ordinate system, x-value should come to 0 as it is a uniform object. Am I right? Please help me!
 
Physics news on Phys.org
The height of the rectangle is not a... it is \sqrt{a^2 - x^2}.
 

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