Calculate the center of mass on the force plate

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SUMMARY

The discussion focuses on calculating the center of mass on a force plate using the formula for xcg and ycg. The formula provided is xcg = (x1M1 + x2M2 + x3M3 + x4M4) / (M1 + M2 + M3 + M4), where the coordinates are determined by placing the lower left node at (0,0). The calculations presented confirm that this method accurately describes the center of mass without altering its actual position, as the choice of origin does not affect the outcome.

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Jim Newt
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Homework Statement



The attached jpeg shows a force plate with four measured masses each corresponding to a corner node. Calculate the center of mass on the force plate.



Homework Equations



I think they would be:

xcg = (x1M1 + x2M2 + x2M3 + x4M4) / (M1 + M2 + M3 + M4)

The ycg would be the same except you put yn in for xn.


The Attempt at a Solution



The textbook I've seen will place the lower left node at (0,0), thus zeroing out two of the nodes in each calculation. How does this give an accurate answer?

So for this method, the xcg would be:

xcg = (19*20 + 9*20) / (20 + 42 + 9 + 19)

Is this correct?
 

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Jim Newt said:
The textbook I've seen will place the lower left node at (0,0), thus zeroing out two of the nodes in each calculation. How does this give an accurate answer?
They are just choosing a reference point for describing the coordinates. They chose the origin to be at the lower left. No problem--it doesn't change where the center of mass is, just how you describe it.

So for this method, the xcg would be:

xcg = (19*20 + 9*20) / (20 + 42 + 9 + 19)

Is this correct?
Sure. Why not? Note that this is consistent with the formula you gave.
 

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