The problem involves calculating the force on the tight side of a belt drive, given parameters such as the belt coefficient of friction, pulley diameter, and maximum torque. The context is within the subject area of mechanics, specifically focusing on belt drives and torque relationships.
Participants are actively exploring the relationships between the forces and tensions involved. Some have pointed out potential misunderstandings regarding the definitions of maximum torque and the conditions under which the equations apply. There is recognition of the need to find T1 and T2, with multiple equations being considered for further analysis.
There is an acknowledgment that the information provided may only allow for the determination of minimum tensions, and discussions about the implications of slipping versus non-slipping conditions are ongoing.
TSny said:Does "maximum torque" refer to the net torque due to both T1 and T2? If so, then I don't think T2 = 400 N.
Think about how T1 and T2 are related to the 400 N force that you calculated from the max torque.Girn261 said:now I need to find T2 & T1.. hmm
T1-T2=400N Max torque.. hmm, now two unknownsTSny said:Think about how T1 and T2 are related to the 400 N force that you calculated from the max torque.
TSny said:..and two equations
I don't understand this. What's wrong with your original equation T2=T1/eμθ ? (The tool bar has editing tools for superscripts, etc. Σ on the tool bar will bring up math symbols.)Girn261 said:F2^e*friction*angle - F1/e*friction*angle = 400N.
I would just like to point out that there is only enough information to find the minimum tensions. Any equal increase on that to both tensions will still satisfy the conditions.Girn261 said:Calculate the force on the tight side
Would the condition T1 = eμθ T2 still be satisfied?haruspex said:I would just like to point out that there is only enough information to find the minimum tensions. Any equal increase on that to both tensions will still satisfy the conditions.
That is not a given condition. It is just like linear friction: if slipping, T1 = eμkθ T2; if not slipping T1 ≤ eμsθ T2.TSny said:Would the condition T1 = eμθ T2 still be satisfied?
Yes, I see that now. Thanks, haruspex.haruspex said:That is not a given condition. It is just like linear friction: if slipping, T1 = eμkθ T2; if not slipping T1 ≤ eμsθ T2.