Calculate the force required to pull the truck

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SUMMARY

The discussion focuses on calculating the forces involved in moving a 110 kg trunk across a floor at constant velocity. The coefficient of kinetic friction (μk) is determined to be 0.35 using the equation μ = Ff/Fn, where Ff is the frictional force and Fn is the normal force. When a friend pulls with an additional force of 150N upwards, the required force to maintain constant velocity is calculated to be 566N, factoring in the new normal force. The discussion emphasizes the importance of free-body diagrams for accurate force analysis.

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Homework Statement


You are dragging a 110 kg trunk across a floor at a constant velocity with a horizontal force of 380N.
a) Calculate the coefficient of kinetic friction
b)A friend decides to help by pulling on the truck with a force of 150N [up]. Will this help? Calculate the force required to pull the truck at a constant velocity to help you decide.
c) Instead of pulling on the trunk, your 55 kg friend just sits on it. What force is required to keep the trunk moving at a constant velocity?

Homework Equations


μ=Ff/Fn

The Attempt at a Solution



a) μk= Fk/Fn
= 380/(110x9.8)
μk = 0.35

b)

c) Fk = μkFn
= (0.35)(165x9.8)
Fk = 566N

Did I solve a) and c) correctly? Also how would I go about doing b).
 
Last edited:
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(a) sort of - you should start from a free-body diagram, which makes the equations look different.
(b) use a free-body diagram
(c) again - sort of - same reason. Where did you get that relationship from? (i.e. to add the masses.)
 

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